Question

Prove that
(Sin A+ Cosec A) + (Cos A + Sec A) = 7 + tanº A + Cot A​

Answer 1

Answer:

hence we can prove it but your question is wrong it should be squared on both the sides.

Explanation:

Firstly square on both the sides ,

               (sinA+cosecA)^{2} +(cosA+secA)^{2} = 7+tan^{2} +cot^{2}

here starts,

        LHS:

             =sin^{2}A + cosec^{2} A + 2 sinA cosecA + cos^{2} + sec^{2} + 2 cosA secA.

            = 1+2+2+1+cot^{2} +1+tan^{2}

            =7+tan^{2} + cot^{2}[/tex].

LHS=RHS

Answer 2

Answer:

tnx for this question guys

Explanation:

plz mark me as brainliest