Question

PROVE that (sin A+cosec A)sq + (cos A+sec A)sq = 7+tan sq A+cot sq A.

Please very urgent(︶^︶)​

Answer 1

Answer:

formula...which were used here....

sin^2A + cos^2A = 1

cosec^2A - cot^2A = 1

sec^2A - tan^2A = 1

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Answer 2

(cosec x-cot x)^2 = ((1-cos x)/(1+cos x))

[(1/sin x) - (cos x/sin x)]^2 = [2.(sin (x/2))^2]/[2.(cos (x/2))^2]

((1-cos x)/sin x)^2 = [tan(x/2)]^2

{[2.(sin (x/2))^2]/[2.sin(x/2).cos (x/2)]}^2 = [tan(x/2)]^2

[sin(x/2) / cos(x/2) ]^2 = [tan(x/2)]^2

[tan(x/2)]^2 = [tan(x/2)]^2

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