Question

prove that sin A ×secA ×root of cosec square A-1 =1

Answer 1

Hi ,

SinA secA × √( cosec² A - 1 ) = 1

LHS = sinAsecA (√cosec² A - 1 )

= sinA / cosA [ √ cot² A ]

[ Since 1 ) secA = 1/cosA

2 ) cosec² A - 1 = cot² A ]

= tan A cotA

= 1

[ Since tanAcotA = 1 ]

= RHS

I hope this helps you.

: )

Answer 2

heya..!!!

we know that:-

secA = 1/cosA
cosec²A - 1 = cot²A
cotA = 1/tanA

now,


sinA × secA × √(cosec² - 1)

= sin/cosA × √(cot²A)
[ (cosec²A - 1) = cot²A ]

= tanA × cotA

= tanA × 1/tanA

= 1

I HOPE ITS HELP YOU,