Question

Prove that : Sin A / Sin (90°- A) + Cos A / Cos (90°-A)= Sec (90°-A) Cosec (90°-A)

Please do and show in a notebook

Answer 1

Answer:

Step-by-step explanation:

L.H.S

Sin A/Sin (90°-A) + Cos A/ Cos(90°-A)

=Sin A / Cos A + Cos A/Sin A

=(Sin²A+Cos²A)/Sin A *Cos A

=1/SinA*CosA

=(1/Sin A) * (1/Cos A)

=Cosec A * Sec A

=Sec(90°-A) Cosec (90°-A)=R.H.S

Answer 2

Answer:

Answer is given in the picture

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