Question

prove that : sin A / sin (90°-A) + cos A / cos ( 90°-A ) = secA cosec A​

Answer 1

Step-by-step explanation:

Given that

sinA/sin(90-A) +cosA/cos(90-A)

sinA/cosA+cosA/sinA (sin(90-A)=cosA

on taking lcm

sinA.sinA+cosA.cosA/sinA.cosA

sin sqareA+cos square A/sin AcosA

1/sinAcosA

cosecA.secA 1/sinA=cosecA and 1/cos A=secA

Answer 2

Hope this helped you