Question

Prove that :



sin A. tan A ÷ 1- cos A = 1 + sec A



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Answer 1

Answer:

SinA*sinA/cosA) /(1-cosA)

sin^2A/(cosA (1-cosA ))

(1-cos^2A)/ (cosA (1-cosA))

(1+cosA)(1-cosA) / (cosA (1-cosA))

(1+cosA)/cosA

(1/cosA)+(cosA/cosA)

secA+1

1+secA proved

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