Question

Prove that sin A tanA /1-cos A = 1+ secA

Answer 1

LHS = Sin A.Tan A.(1/1-Cos A)

=Sin A. (SinA/CosA).(1/1-CosA)

=(Sin2A)/(CosA.(1-CosA)

=(1-Cos2A)/( CosA.(1-CosA)

=(1+CosA)(1-CosA)/ CosA.(1-CosA)

=(1/cosA)+(CosA/CosA)

=SecA+1=RHS

Hence Proved