Question

Prove that sin A x tan A/ 1- cosA = 1 + sec A

Answer 1

How do I prove sinA-cosA+1/sinA+cosA-1=1/secA-tanA?

Hi,

LHS = sinA-cosA+1/sinA+cosA-1

divide both numerator and denominator by cosA

LHS=(tanA−1+secA)/(tanA+1−secA)

Now

sec2A=1+tan2A

sec2A−tan2A=1

Using above relation at denominator of LHS

LHS=(tanA−1+secA)/(tanA−secA+sec2A−tan2A)

LHS=(tanA−1+secA)/((secA−tanA)(−1+secA+tanA))

LHS=1/(secA−tanA)

LHS=RHS

Hence Proved.

Answer 2

Answer:

Step-by-step explanation:

I am sorry to say that I think the question may be wrong can you please check it again?