prove that sin b + c upon 2 is equal to Cos A upon 2
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Step-by-step explanation:
a+b+c=180
b+c=180-a
sin(b+c/2)=sin(180-a/2)
=sin(90-a/2)
=cos(a/2)
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The perimeter of triangle is a+b+c=180 ...after that we divide it by 2
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