Question

Prove that
(sin θ +cos θ )^2 = 1+2 sinθ.cosθ​

Answer 1

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Answer 2

${( \cos( \theta) + \sin( \theta)) }^{2} = 1 + 2 \sin( \theta) . \cos( \theta) \\ { \cos}^{2} \theta + {sin}^{2} \theta + 2 \sin( \theta) . \cos( \theta) = 1 + 2 \sin( \theta) . \cos( \theta) \\ 1 + 2 \sin( \theta) . \cos( \theta) = 1 + 2 \sin( \theta) . \cos( \theta)$

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