Question

Prove that :

( sin θ cos (90- θ) cos θ )/( sin (90- θ) ) + ( cos θ sin (90- θ) sin θ )/( cos (90- θ) ) = 1

Answer 1

Answer:

Step-by-step explanation:

cos(90-Θ)=sinΘ

sin(90-Θ)=cosΘ

RHS=1

LHS:

(sinΘcos(90-Θ)cosΘ)/sin(90-Θ) + (cosΘsin(90-Θ)sinΘ)/cos(90-Θ)

=(sinΘsinΘcosΘ/cosΘ)+(cosΘcosΘsinΘ/sinΘ)

=(sin²Θ+cos²Θ)

=1

∴LHS=RHS=1

Hence proved.