Question

Prove That : sinθ.cos(90-θ)cosθ/sin(90-θ) + cosθ.sin(90-θ)sinθ/cos(90-θ) = 1 pl ans yaar its urgent....I have to submit in a very limited time

Answer 1

Answer:

sin·sin x cos/cos +cos ·cos·sin/sin

sin²+cos²

since sin²+cos²=1

hence proved

the 1st step was unchanged just the following complement is used

sin thita=cos(90-thita)and the second is cos thita=sin(90-thita)

Answer 2

sin theta.sin theta cos theta /cos theta +cos theta .cos theta sin theta /sin theta =1

sin² theta +cos² theta=1