Question

prove that sin∅-cos∅/sin∅+cos∅+ sin∅+cos∅/sin∅-cos∅=2/2sin²∅-1

Answer 1

Step-by-step explanation:

L.H.S:-

(sinA-cosA)²+(sinA+cosA)²/sin²A-cos²A

=sin²A-2sin.AcosA+cos²A+sin²A+2sin²A.cos²A+cos²A/sin²A-cos²A

=2(sin²A+cos²A)/sin²A-(1-sin²A)

=2/2sin²A-1. [*phi replaced by A ]