Prove that: (sinθ - cosecθ)(cosθ - secθ)=1/tanθ+cotθ right answer will be marked brainliest.. please help!
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Step-by-step explanation:
LHS=(1/sinФ - sinФ) (1/cosФ -cosФ)
=((1-sin²Ф)/sinФ) ((1-cos²Ф)/cosФ)
=(cos²Ф/sinФ) (sin²Ф/cosФ)
=cosФsinФ ----1
RHS = 1/(sinФ/cosФ +cosФ/sinФ)
=1/((sin²Ф+cos²Ф)/(sinФcosФ))
=1/(1/cosФ)(1/sinФ)
=cosФsinФ----2
LHS = RHS
(cosecФ-sinФ)(secФ-cosФ)=1/tanФ+cotФ
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