Question

prove that( sin cube +cos cube ÷sin + cos). + sin cos =1​

Answer 1

Answer:

Step-by-step explanation:

sin³ + cos³ / sin + cos + sin cos

sin + cos x sin² - sin  cos + cos²/ sin + cos + sin cos

( Identity :- a³ + b³ = a+ b x a² - ab + b²)

= sin + cos x 1 - sin cos / sin + cos + sin cos

= 1 - sin cos + sin cos

= 1

Hence Proved

Answer 2

Answer:

Step-by-step explanation:

(sin^3 + cos^3) ÷ sin + cos + sin×cos =1

(a^3+b^3) = (a+b) (a^2+b^2-ab)

Similarly,

(sin+cos) (sin^2+cos^2-sin cos)÷ (sin + cos) + sin cos

1-sin cos + sin cos. (After cancellation)

= 1

Hence proved