Question

Prove that
Sin o - 2sin^3 o / 2cos^3 -cis o = tan o

Answer 1

Answer:

Step-by-step explanation:

LHS:

sin o (1-2sin^2 o) / cos o(cos^2o-1)

as sin o/ cos o=tan o

tan o (1-2sin^2 o)/(cos^2o-1)

as sin^2o=1-cos^2o

tan o (1-2(1-cos^2o) / (cos^2o-1))

tan o(cos^2o-1/cos^2o-1)

tan o * 1= RHS