Question

prove that sin power 6 theta + cos power 6 theta equals to 1 - 3 sin square theta cos square theta​

Answer 1

Answer:

Step-by-step explanation:

To prove :- sin^6theta +cos^6theta = 1 - 3sin^2theta.cos^2theta

proof:- (sin^2theta)^3 + (cos^2theta)^3

       (by identity :- a^3 + b^3 = (a + b)^3 - 3ab(a+b) )

= (sin^2theta + cos^2theta)^3 - 3sin^2cos^2(sin^2 + cos^2)

= 1 - 3sin^2cos^2