Question

prove that sin sq. thita + 5 cos sq. thita +2=4cos sq. thita +3​

Answer 1

Answer:

sin²θ+5cos²θ+2=4cos²θ+3

(sin²θ+cos²θ)+4cos²θ+2=4cos²θ+3

1+4cos²θ+2=4cos²θ+3

4cos²θ+2+1=4cos²θ+3

4cos²θ+3=4cos²θ+3

LHS=RHS

Hence proved