Question

Prove that sin square 73 + sin square 17 upon cos square 28 + cos square 62 equal to 1

Answer 1

Answer:

sin square 73 + sin square 17/ cos square 28 + cos square 62 = 1

Step-by-step explanation:

sin square 73 + sin square 17/cos square 28 + cos square 62

Sin square 73 + Cos square 73 / Sin square 62 + Cos square 62

{Sin (90 - 73) = cos 73}

{cos (90- 62)= sin 62}

1/1= 1

{Sin square theeta+ cos square theeta = 1; here theeta = 73 and 62}