Question

prove that sin square A + cos square A . tan square A = 2 sin square A​

Answer 1

Answer:

Step-by-step explanation:

sin²A  + cos²A × sin²A/cos²A      ( tan A = sin A/cos A)

= sin²A + sin²A

=2 sin² A

Answer 2

Solution →

$</strong><strong>=</strong><strong> </strong><strong>{sin}^{2}a + {cos}^{2}a \times {tan}^{2}a$

$</strong><strong>=</strong><strong>{sin}^{2} a + {cos}^{2} a \times \frac{ {sin}^{2}a }{ {cos}^{2}a }$

Cos²a will be cancelled by Cos²a ,

$</strong><strong>=</strong><strong> {sin}^{2} + {sin}^{2} a$

$\boxed{=2 sin^{2}a}$

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