Question

Prove that sin square A cos square B - cos square A sin square B = sin square A - sin square B

Answer 1

$\sin^2A\cos^2B-\cos^2A\sin^2B=\sin^2A-\sin^2B$ proved.

Step-by-step explanation:

Consider the provided information.

$\sin^2A\cos^2B-\cos^2A\sin^2B=\sin^2A-\sin^2B$

Consider the LHS.

$\sin^2A\cos^2B-\cos^2A\sin^2B$

$\sin^2A(1-\sin^2B)-(1-\sin^2A)\sin^2B$               (∴$\cos^2x=1-\sin^2x$)

$\sin^2A-\sin^2A\sin^2B-\sin^2B+\sin^2A\sin^2B$

$\sin^2A-\sin^2B$

Hence, proved.

#Learn more

Prove that

Sin80 -cos110 = root3sin50

https://brainly.in/question/13091100

Answer 2

very good thanks for ur answer