Prove that sin square a + sin square b minus sin square c = 2 sin a sin b cos c
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question is incomplete in my view.
I think there should be
a+b+c=π
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Secondary School Math 5+3 pts
Prove that sin square A cos square B - cos square A sin square B = sin square A - sin square B
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by Shakeelbinjaleel6 18.08.2019
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FelisFelisAmbitious
\sin^2A\cos^2B-\cos^2A\sin^2B=\sin^2A-\sin^2B proved.
Step-by-step explanation:
Consider the provided information.
\sin^2A\cos^2B-\cos^2A\sin^2B=\sin^2A-\sin^2B
Consider the LHS.
\sin^2A\cos^2B-\cos^2A\sin^2B
\sin^2A(1-\sin^2B)-(1-\sin^2A)\sin^2B (∴\cos^2x=1-\sin^2x)
\sin^2A-\sin^2A\sin^2B-\sin^2B+\sin^2A\sin^2B
\sin^2A-\sin^2B
Hence, proved.