prove that sin square theta + cos square theta is equal to 1
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to prove
(sin theeta)^2 + (cos theeta)^2 = 1
perpendicular = p
base = b
hypotenuse = h
proof
sin theeta = p/h
cos theeta = b/h
(sin theeta)^2 + (cos theeta)^2
(p/h)^2 + (b/h)^2
p^2 /h^2 + b^2 /h^2
(p^2 +b^2)/h^2.........(p^2 +b^2=1 by
pythagores theorem)
h^2/h^2 = 1
prooved
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