Question

prove that sin square theta + cos square theta is equal to 1​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Given:

Prove that sin square theta + cos square theta is equal to 1

Solution:

Put sin \theta = \frac{P}{H}, cos \theta = \frac{B}{H},

Sin^2 \theta + Cos^2 \theta= 1

(\frac{P}{H})^2 + (\frac{B}{H})^2 = 1

\frac{(P^2 + B^2)}{H^2} = 1

Ina triangle, by pythogoras,

P^2 + B^2 = H^2

Hence, \frac{H^2}{H^2} = 1.

Hence proved