Question

prove that sin square theta upon cos theta + cos theta is equal to sec theta
please solve this​

Answer 1

Solution :

= Sin²θ / Cos θ + Cos θ

= Sin²θ + Cos²θ / Cos θ

= 1 / Cos θ

= Sec θ. [ •°• 1/Cos θ = Sec θ ]


Trigonometry Identity Used !

: Sin²θ + Cos²θ = 1

: 1/Cos θ = Sec θ

Answer 2

$\huge\mathfrak{ANSWER:-}$

$\frac{ { \sin}^{2 } \alpha }{ \cos( \alpha ) } + \cos( \alpha ) \\ \\ \\ = \frac{ { \sin }^{2} \alpha }{ \cos( \alpha ) } + \frac{ { \cos }^{2} \alpha }{ \cos( \alpha ) } \\ \\ \\ = \frac{ { \sin }^{2} \alpha + { \cos }^{2} \alpha }{ \cos( \alpha ) } \\ \\ \\ = \frac{1}{ \cos( \alpha ) } \\ \\ \\ = \sec( \alpha ) \\ \\ \\ = rhs$

Thank you.