prove that sin square thetha plus cos square thetha is 1
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take a trialngle ABC where C is 90 degree.
the perpendicular is AC and adjacent is BC when we take angle B as a reference.
so sinB=AC/AB and cosB=BC/AB.
sin square B + cos square B=(( AC)^2 +(BC)^2)/(AB)^2.
this is equal to (AB)^2/(AB)^2. {using pythagoras theeram}
(sin square B) plus (cos square B )=1
the perpendicular is AC and adjacent is BC when we take angle B as a reference.
so sinB=AC/AB and cosB=BC/AB.
sin square B + cos square B=(( AC)^2 +(BC)^2)/(AB)^2.
this is equal to (AB)^2/(AB)^2. {using pythagoras theeram}
(sin square B) plus (cos square B )=1
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Sin squad theta plus cos squad theta is equal
Step-by-step explanation:
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