Question

prove that sin square tita +cos square tita =1​

Answer 1

to prove sin²∅+cos²∅=1

proof

h²=p²+b²

ac²=ab²+bc²

let ∠a be ∅

ac²/ac²=ab²/ac²+bc²/ac²

1=cos²∅+sin²∅

Answer 2

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Sin²∅ + Cos²∅ = 1

$Prove$ =>

$\bold{LHS}$ Sin²∅ + Cos²∅ = 1

$We \ know \ that$

Sin∅ = $\frac{perpndicular}{height}$

and Cos²∅ = $\frac{base}{height}$

$( \: \frac{p}{h} ) {}^{2} + (\frac{b}{h} ) {}^{2}$

$\frac{p {}^{2} + {b}^{2} }{h {}^{2} }$

In ∆ p² + b² = h² ( $By \ Pythagoras \ theorem$ )

So ,

$\frac{h {}^{2} }{h {}^{2} } = \: 1 \: \: rhs$

LHS = RHS

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