Prove that ( sin theata + 1 + cos theata ) ( sin theata - 1 + cos theata ) . Sec theata cosec theata =2
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Step-by-step explanation:
(Sinθ + 1 + Cosθ)(Sinθ - 1 + Cosθ)Secθ*Cosecθ
= (Sinθ + Cosθ + 1) (Sinθ + Cosθ - 1)Secθ*Cosecθ
= [(Sinθ + Cosθ)² - (1)²]Secθ*Cosecθ
= [(Sinθ + Cosθ)² - 1]Secθ*Cosecθ
= [Sin²θ+ Cos²θ+2SinθCosθ - 1]Secθ*Cosecθ
= [1 + 2SinθCosθ - 1]Secθ*Cosecθ
= (2SinθCosθ)Secθ*Cosecθ
= 2SinθCosθ / SinθCosθ
= 2
= R.H.S
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