Prove that :- sin theta/ 1 - cos theta + tan theta/ 1 + cos theta = sec theta. cosec theta + cot theta
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Answer:
Sinθ/(1 - cosθ) + Tanθ/(1 + cosθ) = Secθ.Cosecθ + Cotθ
Step-by-step explanation:
Sin theta/1-cos theta + tan theta / 1+cos theta = sec theta.cosec theta + cot theta
Sinθ/(1 - cosθ) + Tanθ/(1 + cosθ) = Secθ.Cosecθ + Cotθ
LHS = Sinθ/(1 - cosθ) + Tanθ/(1 + cosθ)
= (sinθ(1 + cosθ) + Tanθ(1-Cosθ))/(1 - Cos²θ)
= (sinθ(1 + cosθ) + (Tanθ - Sinθ)) /Sin²θ
= ( 1 + cosθ + 1/Cosθ - 1)/Sinθ
= (cosθ + 1/Cosθ)/Sinθ
= 1/CosθSinθ + cosθ/Sinθ
= Secθ.Cosecθ + Cotθ
= RHS
QED
Proved
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