Question

prove that sin theta + cos theta upon sin theta minus cos theta + sin theta minus cos theta upon sin theta + cos theta is equals to 2 sec squared theta upon tan squared theta minus one

Answer 1

Answer:In the figure

Step-by-step explanation:

Remember that

(a+b)^2 = a^2 + b^2 + 2ab

(a+b)(a-b) = a^2 - b^2

Answer 2

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