prove that:(sin theta - cosec theta)(cos theta -sec theta)=1/tan theta + cot theta
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Step-by-step explanation:
LHS
(sin-cosec)(cos-sec)
=(sin²-1)(cos²-1)/sincos
=(1-sin²)(1-cos²)/sincos
=sin²cos²/sincos
=sincos
RHS
1/tan+cot
=1/(sin/cos+cos/sin)
=1/(sin²+cos²/sincos)
=sincos
hence, LHS=RHS
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