prove that sin theta(cosec theta-sin theta)=cos² theta
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Answer:
LHS=sinθ÷cos2θ−cosecθ+sinθ
=sinθ÷cos2θ−sinθ1+sinθ
=sinθ÷cos2θ−1+sin2θ
=sinθ÷1−1
=0
=RHS
Hence proved
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Answer:
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