Math, asked by nizam37, 1 year ago

Prove that (sin theta+cosec theta)sqare+(cos theta+sec theta)sqare --(tansqare theta+ cot square theta)=7

Answers

Answered by Nishant5910
0
L.H.S.= sin^2theta + cosec^2theta+ 2sinthetacosectheta +cos^2theta + sec^2theta + 2costhetasectheta - tan^2theta - cot^ 2theta
=1 + 1 + tan^2theta + 2 + 1 + cot^ 2theta + 2 - tan^2theta - cot^ 2theta
=7


RHS=LHS
Hence proved
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