Math, asked by AbhinavKumar2316, 2 months ago

prove that sin theta/sin(90-theta) + cos theta/cos(90-theta) =sec theta*cosec theta(no spamming)​

Answers

Answered by Saswatkumarsahu
1

sin theta/sin(90-theta) + cos theta/cos(90-theta) = sec theta × cosec theta

sin theta/ cos theta + cos theta/sin theta

sin*2 theta + cos*2 theta/ cos theta× sin theta

1 / cos theta sin theta= sec theta cosec theta

1/ cos theta× 1 sin theta

sec theta * cosec theta = R.H.S

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