prove that sin theta sin(90°-theta)- cos theta cos(90°- theta)=0.
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HOLA
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We know that , Sin ( 90 - theta) = Cos theta
Cos ( 90 - theta ) = Sin theta
So here we have ,
Sin theta - Sin(90 - theta) - Cos theta - Cos(90 - theta )
Sin theta - Cos theta - Cos theta - Sin theta = 0
So , RHS = LHS
≠=====================>>
HOPE U UNDERSTAND
Any Doubts comment below
==============================
We know that , Sin ( 90 - theta) = Cos theta
Cos ( 90 - theta ) = Sin theta
So here we have ,
Sin theta - Sin(90 - theta) - Cos theta - Cos(90 - theta )
Sin theta - Cos theta - Cos theta - Sin theta = 0
So , RHS = LHS
≠=====================>>
HOPE U UNDERSTAND
Any Doubts comment below
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