Prove that
sin thit + sin
2 thita
1+ COS thita + COS2 thita
tan
Answers
Answered by
1
Reminder :
sin
(
2
θ
)
=
2
sin
θ
cos
θ
cos
(
2
θ
)
=
2
cos
2
θ
−
1
tan
θ
=
sin
θ
cos
θ
Therefore,
L
H
S
=
sin
θ
+
sin
2
θ
1
+
cos
θ
+
cos
2
θ
=
sin
θ
+
2
sin
θ
cos
θ
1
+
cos
θ
+
2
cos
2
θ
−
1
=
sin
θ
(
1
+
2
cos
θ
)
cos
θ
(
1
+
2
cos
θ
)
=
tan
θ
=
R
H
S
I hope it's helpful to you....
Answered by
0
Answer:
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