Question

prove that sin thita - 2 sin ^3 thita / 2 cos ^3 - cos thita = tan thita​

Answer 1

(sin theta - 2sin^3 theta)/(2cos^3 theta - cos theta)

= sin theta(1 - 2sin^theta)/cos theta(2cos^2 theta -1)

= sin theta(cos 2theta)/cos theta(cos 2theta)

= sin theta/ cos theta

= tan theta     $hence\ proved$

NOTE: COS 2THETA = 1 - SIN^2 THETA = COS^2 THETA -1

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