prove that (sin thita + cosec thita) square +( cos thita + sec thita) square =7 +tan square thita +cot square.
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LHS=sin^2 thita + cosec^2thita + 2×sin thita ×cosecthita + cos^2 thita +sec^2 thita +2×cos thita×sec thita
=(sin^2 thita +cos^2 thita) +2+2+cosec^2thita + sec ^2thita
= 1+2+2+(1+cot^2 thita )+1+tan^2 thita
=7 +cot^2+ tan^2= RHS
LSH =RHS
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