Question

prove that (sin tita+1+cos tita) (sin tita -1+ cos tita) sec tita cosec tita = 2

​

Answer 1

LHS

= (sin theta +cos theta+1 )(sin theta +cos theta - 1) (sec theta cosec theta)

= (sin theta +cos  theta)^2 - 1 (sec theta cosec theta)

= sin^2 theta + cos ^2 theta+ 2 sin theta cos theta -1 (sec theta cosec theta)

= 1+2 sin theta cos theta -1  (sec theta cosec theta)

= 2 sin theta cos theta 1/cos theta 1/sin theta

=2

hence proved

please mark as brainliest