prove that (sin tita+1+cos tita) (sin tita -1+ cos tita) sec tita cosec tita = 2
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= (sin theta +cos theta+1 )(sin theta +cos theta - 1) (sec theta cosec theta)
= (sin theta +cos theta)^2 - 1 (sec theta cosec theta)
= sin^2 theta + cos ^2 theta+ 2 sin theta cos theta -1 (sec theta cosec theta)
= 1+2 sin theta cos theta -1 (sec theta cosec theta)
= 2 sin theta cos theta 1/cos theta 1/sin theta
=2
hence proved
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