Question

Prove that:- sin tita tan tita / 1-cos tita = 1 + sec tita
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Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

l.h.s

$= \sin( \alpha ) \times \tan( \alpha ) \div 1 - \cos( \alpha ) \\ = \sin( \alpha ) \ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } \div 1 - \cos( \alpha \\ = \frac{ \ { \sin( \ \alpha ) }^{2} }{ \cos( \alpha )(1 - \cos( \alpha )) } \\ = \frac{1 - { \cos( \alpha ) }^{2}}{cos( \alpha )(1 - \cos( \alpha ))} \\ = \frac{(1 - \cos( \alpha ))(1 + \cos( \alpha )) }{ \cos( \alpha )(1 - \cos( \alpha ) ) } \\ = \frac{1 + \cos( \alpha ) }{ \cos( \alpha ) } \\ = \frac{1}{ \cos( \alpha ) } + 1 \\ = \sec( \alpha ) + 1 \\ = r.h.s$