Question

Prove that sin x - 2sin3x÷2cos3x-cos x =tanx

Answer 1

Answer:

so sin x - 2sin3x /

      2cos3x - cosx                                   = tanx

= sinx(1 - 2sin2x)      /

     cosx(2cos2x - 1)

=sinx[1 -2(1 -cos2x)]

/

  cosx(2cos2x - 1)

=sinx[1 - 2 + 2cos2x]

/

  cosx(2cos2x - 1)

=sinx[2cos2x - 1]

/

    cosx(2cos2x - 1)

= sinx

    cosx

= tanx = rhs

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Answer 2

Answer:

Step-by-step explanation: