Question

prove that

sin ( X +y ) / sin ( X - y ) = tanx +tany /tanx - tany

Answer 1

solution ^^


in question :-

LHS = SIN ( X + Y ) / SIN ( X - Y )

= SINX COSY + COSX SINY / SINX COSY - COSX SINY .

DIVIDE THE NUMERATOR AND DENOMINATOR BY COSX COSY , THEN FIND ,


= SIN(X+Y) / SIN(X-Y) = tanx + tany / tanx - tany.


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