Question

prove that (sin0-2sin^30)/(2cos^30-cos0)=tan0​

Answer 1

Step-by-step explanation:

SinO(1-2Sin²O)/CosO(2Cos²O-1)

{ Cos2O = 2Cos²O-1 = 1-2Sin²O }

SinO*Cos2O/CosO*Cos2O

SinO/CosO

= tanO

Answer 2

Answer:

we know that sin0=0

=sin0-2sin^30/2cos^30-cos0

=0-2×(1/2)^2/2×(root3/2)^2-1

=0-2×1/4/2×3/4-1

= -1/2/3/2-1

= -1/2×2/1

= 1

=tan0