Question

Prove that sin0.sin(90-0)-cos0.cos(90/

Answer 1

Answer:

CosA . cos(90-A) - sinA . sin(90-A) = LHS

cosA . sinA - sinA . cosA

cosA.sinA - cosA.sinA = 0

LHS = 0

Hence proved

Answer 2

• cosA. cos(90°-A) - sinA . sin(90°-A)= LHS
• cosA .sinA-sinA .cosA= LHS=0
• Hence Proved
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