Math, asked by bhavsarmanav14, 2 months ago

prove that sin19°+cos11°/cos19°-sin11°=√3

Answers

Answered by mrhimanshuyadav

0

Step-by-step explanation:

sinA +sinB = 2sin A+B/2×cos A-B/2

SinA -Sin B= 2sin A-B/2×cos A+B/2

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