Question

prove that sin²(40+x)+sin²(50-x)=1

Answer 1

I am taking x as β
${sin}^{2}({40}^{0}+\beta)+{sin}^{2}({50}^{0}-\beta)=1\\=>{sin}^{2}({40}^{0}+{50}^{0}-\beta +\beta)=1\\=>{sin}^{2}{90}^{0}=1\\{sin}^{}{90}^{0}\times 1=1\\=>1=1$