prove that sin²π/6 + sin²π/4 + sin²π/3 = 3/2
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Answered by
0
Step-by-step explanation:
1/4+1/2+3/4= 3/2
as sin π/6=1/2, sin π/4= 1/√2 and sin π/3=√3/2
Answered by
2
Answer:
LHS= (1/2)^2+(1/√2)^2+(√3/2)^2
= 1/4+1/2+3/4
=1/4+1×2/2×2+3/4
=1/4+2/4+3/4
=6/4
=3/2
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