Question

prove that

sin²θ
____ + cosθ = sec θ
cosθ

$pleasge \: answer \: this \: question$
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Answer 1

Answer:

sine ^2 theta / cos theta + cos theta = sec theta

LHS,

=sin^2 theta / cos theta +(cos theta * cos theta )

= sin^2 theta + cos^2 theta / cos theta ( sin^ 2 theta + cos ^2 theta = 1)

= 1/cos theta = sec theta ( 1/cos theta = sec theta)

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Answer 2

Answer:

To prove- (sin²α/cosα)+cosα=secα

Proof-

(sin²α/cosα )+cosα

=(sin²α+cos²α)/cosα

=1/cosα [sin²α+cos²α=1]

=secα

Hence,proved.

*Put theta in place of α