Question

Prove that ( sin² θ + cos²θ = 1 )
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Answer 1

Answer:

Let take Perpendicular as P Base as B and hypotenuse as H

sin^0+cos^0=1

sin=P/H

cos=B/H

Substituting the values

(P/H)^2+(B/H)^2=1

P^2/H^2+B^2/H^2=1

(B^2+P^2)/H^2=1 (P^2+B^2=H^2 {Pythagoras theoram)}

H^2/H^2=1(H^2 canceled)

1=1

Since,LHS=RHS

Hence,proved.

Answer 2

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