Question

Prove that: sin2

(n +1) A - sin2 nA = sin (2n + 1) A sin A.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

sin2(n+1)A - sin2nA = sin(2n+1)A.sinA

we have formula sin2a - sin2b =sin(a-b)sin(a+b)

therefore

sin2(n+1)A - sin2nA=sin[(n+1)A+nA].sin[(n+1)A-nA]

=sin(2n+1)A.sinA =RHS

hence proved